Cartridge Rod Heating Element

The typical structure (the most popular structure) of a cartridge rod heating element is the same as that of a tubular heater. It is generally composed of 5 parts: insulator, sealing material, lead rod, filler, heating wire, metal sheath, and terminal. The spiral heating wire and the lead-out...
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Product Details

The typical structure (the most popular structure) of a cartridge rod heating element is the same as that of a tubular heater. It is generally composed of 5 parts: insulator, sealing material, lead rod, filler, heating wire, metal sheath, and terminal. The spiral heating wire and the lead-out help are located in the center of the metal sheath. Its manufacturing process is to penetrate the spiral heating wire into seamless steel pipe, copper pipe or aluminum pipe. The gap is evenly filled by a multi-tube filling machine. Thermally conductive oxidizing medium, such as crystalline magnesium oxide powder (alumina or clean quartz sand can also be used). Then use a tube shrinking machine to reduce the diameter of the tube to make the oxide medium compact (density reaches 3.3g/cm3 or more) to ensure that the heating wire is isolated from the air, and the center position does not shift and touch the tube wall. such. The heat per unit area can be increased more than ten times. The service life can be correspondingly increased to more than 10 years. 

 CARTRIDGE HEAER

Performance requirements of cartridge rod heating element:

1 heating time

Under the test voltage, the time for the component to rise from the ambient temperature to the test temperature should not exceed 15 minutes

2 Rated power deviation

Under the condition of sufficient heat, the deviation of the rated power of the component should not exceed the range specified below;

For components with rated power less than or equal to 100W: ±10%.

For components with rated power greater than 100W, it is +5%~-10% or 10W, whichever is greater.

3 Leakage current</DIV>

The cold leakage current and the leakage current after the water pressure and sealing test should not exceed 0.5mA

The thermal leakage current at working temperature should not exceed the calculated value in the formula, but the maximum should not exceed 5mA

I=1/6 (tT×0.00001)

I—hot leakage current mA

t—heating length mm

T-working temperature℃

When multiple components are connected in series to the power supply, the leakage current test should be performed on this group of components as a whole.

 Cartridge Heater StructureQQ20200509163519 -

Application range:

1. Mold heating has been accepted by a wide range of customers in modern industrial applications.

2. Heating system in plastic machinery.

3. Pharmaceutical production line.

4. Laboratory heat treatment test.

5. Chemical industry, etc.

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Application-Cartridge Heater

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